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In Mathematics / High School | 2025-07-08

Exercise 1.2 Q.1 Find the products: i) 6 × (-14) ii) -300 × 4 iii) -14 × (-15) iv) -12 × 12

Asked by austingarner6298

Answer (1)

Let's find the products of the given multiplication problems one by one. We'll go through each problem, understanding the rules for multiplying integers.
i) 6 \times (-14)
To find the product of a positive number and a negative number, we multiply their absolute values and the result is negative because the signs are different.
6 × ( − 14 ) = − ( 6 × 14 )
6 × 14 = 84
So, 6 × ( − 14 ) = − 84
ii) -300 \times 4
Similar to the first problem, when one number is negative and the other is positive, the product is negative.
− 300 × 4 = − ( 300 × 4 )
300 × 4 = 1200
Thus, − 300 × 4 = − 1200
iii) -14 \times (-15)
When multiplying two negative numbers, the product is positive because the signs are the same.
− 14 × ( − 15 ) = 14 × 15
14 × 15 = 210
Therefore, − 14 × ( − 15 ) = 210
iv) -12 \times 12
Again, we have one negative and one positive number, so the product will be negative.
− 12 × 12 = − ( 12 × 12 )
12 × 12 = 144
Hence, − 12 × 12 = − 144
By following these steps, you can understand how to multiply integers by considering the sign rules and calculating the absolute values.

Answered by danjohnbrain | 2025-07-21