During a volleyball training session, Keela drank twice as much water as Carol, and Xavier drank 100 ml more water than Keela. Between them they drank 3000 ml of water. How much water did Carol drink?
Answer (1)
To solve this problem, we need to determine how much water Carol drank. Let's break this down step by step.
Let's assume Carol drank C milliliters of water.
According to the problem, Keela drank twice as much water as Carol. So, she drank 2 C milliliters of water.
Xavier drank 100 milliliters more than Keela, so Xavier drank 2 C + 100 milliliters.
The total amount of water consumed by Carol, Keela, and Xavier is given as 3000 ml. Therefore, the equation representing the total water consumption is: C + 2 C + ( 2 C + 100 ) = 3000
Simplifying this equation: C + 2 C + 2 C + 100 = 3000 5 C + 100 = 3000
Subtract 100 from both sides to isolate the terms with C : 5 C = 2900
Divide each side by 5 to solve for C : C = 5 2900 C = 580
So, Carol drank 580 milliliters of water.
