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Questions in Grade High-school

[Terjawab] Fill in the blanks in the tables below. | (-5) x (-3) = 15 | (-6) x (-3) = 18 | (-7) x (-3) = 21 | |---|---|---| | (-5) x (-2) = 10 | (-6) x (-2) = 12 | (-7) x (-2) = 14 | | (-5) x (-1) = 5 | (-6) x (-1) = 6 | (-7) x (-1) = 7 | | (-5) x 0 = 0 | (-6) x 0 = 0 | (-7) x 0 = 0 | | (-5) x 1 = -5 | (-6) x 1 = -6 | (-7) x 1 = -7 | | (-5) x 2 = -10 | (-6) x 2 = -12 | (-7) x 2 = -14 | | (-5) x 3 = -15 | (-6) x 3 = -18 | (-7) x 3 = -21 | | (-5) x 4 = -20 | (-6) x 4 = -24 | (-7) x 4 = -28 |

[Terjawab] Sulfuric acid is manufactured industrially by a four-step process as shown: Step 1: Sulfur is burned in excess air to produce sulfur dioxide. Step 2: Sulfur dioxide is converted into sulfur trioxide. Step 3: Sulfur trioxide is reacted with concentrated sulfuric acid to produce Substance Y. Step 4: Substance Y is reacted with water to produce concentrated sulfuric acid. (a) (i) Name the process used in the industrial manufacture of sulfuric acid. (ii) Identify substance Y produced in Step 3. (b) By writing the balanced chemical equation, describe how sulfur dioxide is converted into sulfur trioxide in Step 2.

[Terjawab] An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?

[Terjawab] Aryson is playing green beans. He has already picked $1\frac{1}{4}$ bushels and picks at a rate of $\frac{7}{8}$ of a bushel each hour. The equation $\frac{7}{8}h + 1\frac{1}{4} = 6$ can be used to represent $h$, the number of hours it will take him to pick 6 bushels. What is the value of h? A. $4\frac{8}{7}$ hours B. $5\frac{3}{7}$ hours C. $5\frac{17}{28}$ hours D. $5\frac{2}{7}$ hours

[Terjawab] A scientist has 100 milligrams of a radioactive element. The amount of radioactive element remaining after [tex]$t$[/tex] days can be determined using the equation [tex]$f(t)=100\left(\frac{1}{2}\right)^{\frac{t}{10}}$[/tex]. After three days, the scientist receives a second shipment of 100 milligrams of the same element. The equation used to represent the amount of shipment 2 remaining after [tex]$t$[/tex] days is [tex]$f(t)=100\left(\frac{1}{2}\right)^{\frac{t-3}{10}}$[/tex]. After any time, [tex]$t$[/tex], the mass of the element remaining in shipment 1 is what percentage of the mass the element remaining in shipment 2? A. 78.1 % B. 81.2 % C. 123.1 % D. 128.0%

[Terjawab] Which best describes why the United States tried to strengthen democracy on a global scale during the Cold War? A. to achieve cooperation and security B. to protect itself from a Soviet invasion C. to secure its economic future D. to guarantee individuals' personal freedoms

[Terjawab] The table shows the distances between a star and three celestial objects. Use the conversion factors to rewrite the distances in different, but equivalent, units. \begin{tabular}{|l|l|} \hline Celestial Objects & Distance from the Star \\ \hline object A & 0.000001877 pc \\ \hline object B & 30.06 AU \\ \hline object C & 778.3 million km \\ \hline \end{tabular} Conversion factors: $1 AU =1.5 \times 10^8 km$ 1 light-year $=9.5 \times 10^{12} km$ 1 parsec $=31$ trillion km , or about 3.262 light-years

[Terjawab] Which equation shows the quadratic formula used correctly to solve $5 x^2+3 x-4=0$ for $x ?$ A. $x=\frac{-3 \pm \sqrt{(3)^2-4(5)(-4)}}{2(5)}$ B. $x=\frac{3 \pm \sqrt{(3)^2+4(5)(-4)}}{2(5)}$ C. $x=\frac{3 \pm \sqrt{(3)^2-4(5)(-4)}}{2(5)}$ D. $x=\frac{-3 \pm \sqrt{(3)^2+4(5)(-4)}}{2(5)}$

[Terjawab] What is the vertex of the graph of $f(x)=|x-13|+11$? A. $(-11,13)$ B. $(-13,11)$ C. $(11,13)$ D. $(13,11)$

[Terjawab] Consider the following intermediate chemical equations: [tex] \begin{array}{ll} C(s)+O_2(g) \rightarrow CO_2(g) & \Delta H_1=-393.5 kJ \\ 2 CO(g)+O_2(g) \rightarrow 2 CO_2(g) & \Delta H_2=-566.0 kJ \\ 2 H_2 O(g) \rightarrow 2 H_2(g)+O_2(g) & \Delta H_3=483.6 kJ \end{array} [/tex] The overall chemical equation is [tex]$C ( s )+ H _2 O ( g ) \rightarrow CO ( g )+ H _2(g)$[/tex]. To calculate the final enthalpy of the overall chemical equation, which step must occur? A. Reverse the first equation, and change the sign of the enthalpy. Then, add. B. Reverse the second equation, and change the sign of the enthalpy. Then, add. C. Multiply the first equation by three, and triple the enthalpy. Then, add. D. Divide the third equation by two, and double the enthalpy. Then, add.