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Questions in chemistry

[Terjawab] How many grams would [tex]$3.36 \times 10^{23}$[/tex] molecules of copper (II) sulfate ([tex]$CuSO_4$[/tex]) weigh? A. [tex]$5.55 g$[/tex] B. 89.03 g C. 8.903 g D. 0.5578 g

[Terjawab] A sample of water with a mass of 648.00 kg at 298 K is heated with 87 kJ of energy. The specific heat of water is [tex]$1 J-1 kg K -1$[/tex]. What is the final temperature of the water? A. 298.00 K B. 298.13 K C. 432.26 K D. 134.26 K

[Terjawab] You reacted 3.5 g of Zn with 75 ml of 0.70 M HCl originally at 23 C and the final temperature of the mixture was 45 C. What is the [tex]$\Delta H_{rn}$[/tex] per mole of zinc reacted? (Check how much Zn reacted, i.e. it may not be limiting)

[Terjawab] What is shown in the table?

[Terjawab] Consider this reaction. [tex]2 Mg(s)+O_2(g) \rightarrow 2 MgO(s)[/tex] What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP? A. 1960 mL B. 2880 mL C. 3710 mL D. [tex]45,100 mL[/tex]

[Terjawab] Consider this reaction: [tex]2 Mg(s)+O_2(g) \rightarrow 2 MgO(s)[/tex] What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP? A. 1860 mL B. 2880 mL C. 3710 mL D. [tex]45,100 dmL[/tex]

[Terjawab] The mass of two samples of copper were measured. What is the total mass, reported to the appropriate number of significant figures? [tex] \begin{array}{r} 1.6524 g \\ +\quad 5.67 g \\ \hline[?] g \end{array} [/tex]

[Terjawab] The mass of two samples of copper were measured. What is the total mass, reported to the appropriate number of significant figures? [tex] \begin{array}{l} 1.6524 g \\ + 5.67 g \\ \hline \end{array} [/tex]

[Terjawab] Which describes the volume of 1 mol of gas at standard temperature and pressure? The volume is greater for a larger mass of gas. The volume is the same for any gas. The volume depends on the size of the container. The volume varies with the pressure.

[Terjawab] Perform the following mathematical operation and report the answer to the correct number of significant figures. [tex]$0.0030 \times 8.65 = \square$[/tex]